Home
Class 12
PHYSICS
To activate the reaction (n, alpha) with...

To activate the reaction `(n, alpha)` with stationary `B^(11)` nuclei, neutrons must have the activation kinetic energy `T_(th) = 4.0 MeV(n, alpha)` means that `n` is bombarded to obtain `alpha`. Find the energy of this reaction.

Text Solution

Verified by Experts

`T_("in") =-(m_(T)+m_(P))/(m_(T)).Q`
`rArr Q = -T_("in")(m_(T))/(m_(T)+m_(P))`
`=-4MeV xx (11)/(11+1) = -3.7 MeV`.
Promotional Banner

Topper's Solved these Questions

  • DAILY PRACTICE PROBLEM

    RESONANCE ENGLISH|Exercise DPP No.31|20 Videos

  • DAILY PRACTICE PROBLEM

    RESONANCE ENGLISH|Exercise DPP No.32|9 Videos

  • DAILY PRACTICE PROBLEM

    RESONANCE ENGLISH|Exercise DPP No.29|20 Videos

  • CURRENT ELECTRICITY

    RESONANCE ENGLISH|Exercise High Level Problems (HIP)|19 Videos

  • ELECTRO MAGNETIC WAVES

    RESONANCE ENGLISH|Exercise Exercise 3|27 Videos

Similar Questions

Explore conceptually related problems

Stationary nucleus ._(92)^(238)U decays by a emission generating a total kinetic energy T: ._(92)^(238)U rarr ._(90)^(234)Th +._2^4 alpha What is the kinetic energy of the alpha -particle?

In a nuclear reaction of alpha - decay, the daughter nuclei ._(Z)^(A)X is moving with kinetic energy E. The total energy released if parent nuclei was at rest will be

what kinetic energy must an alpha -particle possess to split a deuteron H^(2) whose binding energy is E_(b)=2.2 MeV ?

A colliison between reactant molecules must occur with a certain minimum energy before it is effective in yielding Product molecules. This minimum energy is called activation energy E_(a) Large the value of activation energy, smaller the value of rate constant k . Larger is the value of activation energy, greater is the effect of temperature rise on rate constant k . E_(f) = Activation energy of forward reaction E_(b) = Activation energy of backward reaction Delta H = E_(f) - E_(b) E_(f) = threshold energy The activation eneries for forward and backward reactions in a chemical reaction are 30.5 and 45.4 kJ mol^(-1) respectively. The reaction is

A colliison between reactant molecules must occur with a certain minimum energy before it is effective in yielding Product molecules. This minimum energy is called activation energy E_(a) Large the value of activation energy, smaller the value of rate constant k . Larger is the value of activation energy, greater is the effect of temperature rise on rate constant k . E_(f) = Activation energy of forward reaction E_(b) = Activation energy of backward reaction Delta H = E_(f) - E_(b) E_(f) = threshold energy For the following reaction at a particular temperature, according to the equations 2N_(2)O_(5) rarr 4NO_(2)+O_(2) 2NO_(2) + (1)/(2)O_(2) rarr N_(2)O_(5) The activation energies are E_(1) and E_(2) , respectively. Then

A neutron with kinetic energy K=10 MeV activates a nuclear recation, n+ ^(12)C rarr ^(9)Be +alpha whose threshold E_(th)=6.17 MeV .Find the kinetic energy of the alpha particles outgoing at right angles to the direction of the incoming neutron.[Take mu=931.1 MeV ]

A stationary radioactive nucleus of mass 210 units disintegrates into an alpha particle of mass 4 units and residual nucleus of mass 206 units. If the kinetic energy of the alpha particle is E, then the kinetic energy of the residual nucleus is

A nucleus of mass 220 amu in the free state decays to emit an alpha -particle . Kinetic energy of the alpha -particle emitted is 5.4 MeV. The recoil energy of the daughter nucleus is

A proton is bombarded on a stationary lithium nucleus. As a result of the collision, two alpha -particles are produced. If the direction of motion of the alpha -particles with the initial direction of motion makes an angles cos^-1(1//4) , find the kinetic energy of the striking proton. Given, binding energies per nucleon of Li^7 and He^4 are 5.60 and 7.06 MeV, respectively. (Assume mass of proton ~~ mass of neutron).

Consider a nuclear reaction A+B rarr C . A nucleus A moving with kinetic energy of 5 MeV collides with a nucleus B moving with kinetic energy of 3MeV and forms a nucleus C in exicted state. Find the kinetic energy of nucleus C just after its fromation if it is formed in a state with excitation energy 10 MeV . Take masses of nuclei of A,B and C as 25.0,10.0,34.995 amu , respectively. (1amu= 930 MeV//c^(2)) .