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In determination of young modulus of ela...

In determination of young modulus of elasticity of wire, a force is applied and extension is recorded. Initial length of wire `1m` . The curve between extension and stress is depicted then young modulus of wire will be:

A

`2xx10^(9) N//m^(2)`

B

`1xx10^(9) N//m^(2)`

C

`2xx10^(10)N//m^(2)`

D

`1xx10^(10) N//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta1=(Fl)/(Ay) ,(Deltal)/((F//A))=l/y`=slope of curve
`l/y=((4-2)xx10^(-3))/(400xx10^(3))`
Given `1=1m to y=(4000xx10^(3))/(2xx10^(-3))`
`=2xx10^(9)N//m^(2)`
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