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A conducting rod PQ of length l = 2m is ...

A conducting rod `PQ` of length `l = 2m` is moving at a speed of `2m s^(-1)` making an angle of `30^(@)` with its length. A uniform magnetic field `B = 2T` exists in a direction perpendicular to the plane of motin. Then

A

`V_(A)-V_(B)=8V`

B

`V_(A)-V_(B)=4V`

C

`V_(B)-V_(A)=8V`

D

`V_(B)-V_(A)=4V`

Text Solution

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The correct Answer is:
B
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