Curve in the figure shows an adiabatic compression of an ideal gas from `15 m^(3) to `12 m^(3)`, followed by an isothermla compression to a final volume of `3.0 m^(3)`. There are `2.0 "moles"` of the gas. Total heat supplied to the gas is equal to `: (ln2 = 0.693)`

Options

A. 4521 J
B. `-4521J`
C. `-6653 J`
D. `-8476 J`

Answer

C

Explanation

There is no heat transfer in adiabatic compression. In isothermal process
`Q=W=P_(1)V_(1) ln. (V_(2))/(V_(1))=400xx12 ln 1/4 =-6653 J`