A nucleus of mass `M+Deltam` is at rest and decays into two daughter nuclei of equal mass `(M)/(2)` each. Speed of light is c.
The bonding energy per nucleon for the prent nucleus is `E_(1)` and that for the daughter nuclei is `E_(2)`. Then

Options

A. `(Deltam)/(M+Deltam)`
B. `sqrt((2Deltam)/(M))`
C. `sqrt(Deltam)/(M)`
D. `sqrt((Deltam)/(M+Deltam))`

Answer

B

Explanation

`Q=Delta m c^(2)=(1)/(2)xx((M)/(2))v^(2)+(1)/(2)xx((M)/(2))v^(2)`
`Deltamc^(2)=(1)/(2)xxMv^(2)" "rArrv=csqrt((2Deltam)/(M))`