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Assume that a neutron breaks into a prot...

Assume that a neutron breaks into a proton and an electron. The energy released during this process is (Mass of neutron = `1.6725 xx 10^(-27)` kg, mass of proton = `1.6725 xx 10^(-27)` kg, mass of electron = `9 xx 10^(-31)` kg)

A

`0.73 MeV`

B

`7.10 MeV`

C

`6.30 MeV`

D

`5.4 MeV`

Text Solution

Verified by Experts

The correct Answer is:
A

`._(0)n^(1)rarr._(1)H^(1)+._(-1)e^(0)+overset(-)v+Q`
`Deltam+m_(n)-m_(alpha)=m_(e )`
`=(1.6725xx10^(-27)-1.6725xx10^(-27)-9xx10^(-31))kg`
`= -9xx10^(-31) kg`
Energy `=9xx10^(-31) kg`
`=0.511 MeV`
Which is nerarly equal to `0.73 MeV` but as energy will be required.
Since mass is increasing so answer `= -0.511 MeV`
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Assume that a neutron breaks into a proton and an electron . The energy reased during this process is (mass of neutron = 1.6725 xx 10^(-27) kg mass of proton = 1.6725 xx 10^(-27) kg mass of electron = 9 xx 10^(-31) kg )

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