An element A decays into an element C by a two step process `A to B + ._2He^4` and `B to C + 2e^(-)` .Then,

An element A decays into element C by a two-step process : A rarr B + ._2 He^4 B rarr C + 2 e overline Then.

Define the terms: a. Element b. Atom, c. Molecule.

One mole of an ideal gas is subjected to a two step reversible process (A-B and B-C). The pressure at A and C is same. Mark the correct statement(s) :

A radioactive element A of decay constant lamda_(A) decays into another radioactive element B of decay constant lamda_(B) . Initially the number of active nuclei of A was N_(0) and B was absent in the sample. The maximum number of active nuclei of B is found at t=2. In 2//lamda_(A) . The maximum number of active nuclei of B is

If A={a,b,c} and B={1,2,3,4} . Then all possible ordered pairs such that in each ordered pair the first component is an element of set A and second component is an element of set B are obtained by pairing each element from set A with each element form set B. This can be done by the following scheme:

A radioactive element A on disintegration gives two elements B and C. If B is helium and C is the element of atomic number 90 and atomic mass 234, the element A is:

A set B contain 2007 elements. Let C be the set consisting of subsets of B which contain at most 1003 elements. The number of elements is C is

If each one of the two sets A and B has 3 elements, how many elements are there in AxxB? If three of the elements in AxxB be (2,3),(4,4) and (6,6), find the remaining elements.

In a decay process A decays to B. AtoB . Two graphs of number of nuclei of A and B versus time is given then

A 3xx3 matrix A, with 1st row elements as 2,-1,-1 respectively, is modified as below to get another matrix B. R_1 elements of A go to R_3 of matrix C R_2 elements of A go to R_1 of matrix C R_2 elements of A to R_1 of matrix C R_3 elements of A go to R_2 fo matrix C Now, below operations are done on C as follow, C_1 elements of C go to C_3 of B C_2 elements of C go to C_1 of B C_3 elements of C go to C_2 of B It is found that A = B, then