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The nucleus of .(90)^(230)Th is unstable...

The nucleus of `._(90)^(230)Th` is unstable against `alpha`-decay with a half-life of `7.6xx10^(3)"years"`. Write down the equation of the decay and estimate the kinetic energy of the emitted `alpha`-particle from the following data: `m(._(90)^(230)Th)=230.0381 "amu", m(._(68)^(226)Ra)=226.0254 "amu" m(._(2)^(4)He)=4.0026"amu"`.

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To solve the problem, we will follow these steps: ### Step 1: Write the decay equation The alpha decay of Thorium-230 can be represented as follows: \[ _{90}^{230}\text{Th} \rightarrow _{88}^{226}\text{Ra} + _{2}^{4}\text{He} \] ...
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