Find the kinetic energy, potential energy and total energy in
first and second orbit of hydrogen atom if potential energy in first orbit is taken
to be zero.

Explanation

`E_(1)= -13.60eV K_(1)=-E_(1)=13.60 eV U_(1)2E_(1)=-27.20eV`
`E_(2)=(E_(1))/((2)^(2))= -3.40 eV K_(2)=3.40eV` and `U_(2)= - 6.80eV`
Now, `U_(1)=0,i.e.,` potential energy has been increased by `27.20 eV` while kinetic energy will remain unchanged. So values of kinetic energy, potential energy and total energy in first orbit are `13.60 eV, 0,13.60` respectively and for second orbit these valeus are `3.40 eV, 20.40 eV` and `23.80 eV`.