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When a metalic surface is illuminated wi...

When a metalic surface is illuminated with light of wavelength `lambda,` the stopping potential is V. the same surface is illuminated by light of wavelength `2lambda` the stopping potential is `(V)/(3)` The thershold waelength for the surface is

A

`(4lambda)/(3)`

B

`4 lambda`

C

`6 lambda`

D

`(8lambda)/(3)`

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The correct Answer is:
B
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RESONANCE ENGLISH-ATOMIC PHYSICS-Exercise ( Part II : Only one one correct type)
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