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We may state that the energy E of a phot...

We may state that the energy E of a photon of frequency `nu` is `E =hnu`, where h is a plank's constant. The momentum p of a photon is `p=h//lambda` where `lambda` is the wavelength of the photon. From the above statement one may conclude that the wave velocity of light is equal to

A

`3xx10^(8)ms^(-1)`

B

`(E )/(p)`

C

`Ep`

D

`((E )/(p))^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`C= lambda.v=(h)/(p).(E)/(h)=(E)/(P)`
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