`CH_(3)CH=CH_(2)overset(NBS)rarr A overset(KCN)rarr B overset(OH^(-)//Delta)rarr C overset(P//Br_(2))rarr D overset(NH_(3))rarr E overset(Delta)rarr F`

Answer

To solve the question step by step, we will identify each compound from A to F based on the reactions described.

### Step 1: Identify Compound A
**Reaction:** Prop-1-ene (CH₃-CH=CH₂) reacts with N-bromosuccinamide (NBS).

**Explanation:** NBS is used for allylic bromination. The bromine atom will add to the allylic carbon (the carbon adjacent to the double bond). Thus, we will have:

- Starting compound: CH₃-CH=CH₂
- After reaction with NBS: CH₂Br-CH=CH₂ (Bromine is added to the first carbon next to the double bond)

**Compound A:** CH₂Br-CH=CH₂

### Step 2: Identify Compound B
**Reaction:** Compound A (CH₂Br-CH=CH₂) reacts with KCN.

**Explanation:** In this reaction, the cyanide ion (CN⁻) will attack the carbon bonded to bromine, leading to the elimination of Br⁻. The resulting compound will have a cyanide group:

- After reaction with KCN: CH₂(CN)-CH=CH₂

**Compound B:** CH₂(CN)-CH=CH₂

### Step 3: Identify Compound C
**Reaction:** Compound B (CH₂(CN)-CH=CH₂) undergoes hydrolysis.

**Explanation:** Hydrolysis of the nitrile (CN) group will convert it into a carboxylic acid (COOH). The reaction will yield:

- After hydrolysis: CH₂(COOH)-CH=CH₂

**Compound C:** CH₂(COOH)-CH=CH₂

### Step 4: Identify Compound D
**Reaction:** Compound C (CH₂(COOH)-CH=CH₂) reacts with Br₂ in the presence of red phosphorus.

**Explanation:** This reaction is known as the Hell-Volhard-Zelinsky reaction, where bromine adds to the alpha carbon of the carboxylic acid. The product will be:

- After reaction with Br₂: CHBr-CH=CH₂ (Bromine is added to the alpha carbon)

**Compound D:** CHBr-CH=CH₂

### Step 5: Identify Compound E
**Reaction:** Compound D (CHBr-CH=CH₂) reacts with ammonia (NH₃).

**Explanation:** Ammonia will attack the carbon bonded to bromine, leading to the substitution of bromine with an amine group:

- After reaction with NH₃: CH(NH₂)-CH=CH₂ (Amine replaces bromine)

**Compound E:** CH(NH₂)-CH=CH₂

### Step 6: Identify Compound F
**Reaction:** Compound E (CH(NH₂)-CH=CH₂) is heated.

**Explanation:** Upon heating, the amine group will lead to the elimination of ammonia, resulting in the formation of a double bond:

- After heating: CH=CH-CH₂ (Formation of a double bond)

**Compound F:** CH=CH-CH₂

### Summary of Compounds
- **Compound A:** CH₂Br-CH=CH₂
- **Compound B:** CH₂(CN)-CH=CH₂
- **Compound C:** CH₂(COOH)-CH=CH₂
- **Compound D:** CHBr-CH=CH₂
- **Compound E:** CH(NH₂)-CH=CH₂
- **Compound F:** CH=CH-CH₂