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What is the frequency of revolution of e...

What is the frequency of revolution of electron present in 2nd Bohr's orbit of H-atom?

A

`1.016xx10^(16)s^(-1)`

B

`4.065xx10^(16)s^(-1)`

C

`1.626xx10^(15)s^(-1)`

D

`8.13xx10^(16)s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
4
Frequency of revolution `=("velocity in second orbit "V_(2))/(2pir_(2))`
`=(1.082xx10^(6)ms^(-1))/(2xxpixx(2.12xx10^(-10)))=8.13xx10^(16)s^(-1)`
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