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Be^(3+) and a proton are accelerated by ...

`Be^(3+)` and a proton are accelerated by the same potential. Their de-Broglie wavelengths have the ratio (assume mass of proton=mass of neutron):

A

`1:2`

B

`1:4`

C

`1:1`

D

`1:3sqrt(3)`

Text Solution

Verified by Experts

The correct Answer is:
4
`lambda_(Be^(+3))=(h)/(sqrt(2xx3eVm_(Be^(3+))))=(h)/(sqrt(2xx3eV9m_(p)))`
`lambda_(p)=(h)/(sqrt(2eVm_(p)))`
Hence `(lambda_(Be^(+3)))/(lambda_(p))=sqrt((2eVm_(p))/(2xx3eVxx9m_(p)))=(1)/(3sqrt(3))`
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