A dye absorbs a photon of wavelength `lamda` and re-emits the same energy into two photons of wavelengths `lamda_(1)` and `lamda_(2)` respectively. The wavelength `lamda` is related with `lamda_(1)` and `lamda_(2)` as :

Options

A. `lambda=(lambda_(1)+lambda_(2))/(lambda_(1)lambda_(2))`
B. `lambda=(lambda_(1)lambda_(2))/(lambda_(1)+lambda_(2))`
C. `lambda=(lambda_(1)^(2)lambda_(2)^(2))/(lambda_(1)+lambda_(2))`
D. `lambda=(lambda_(1)lambda_(2))/((lambda_(1)+lambda_(2))^(2))`

Answer

B

Explanation

`E=E_(1)+E_(2),(hc)/(lambda)=(hc)/(lambda_(1))+(hc)/(lambda_(2))" "rArr" "(hc)/(lambda)=hc((lambda_(2)+lambda_(1))/(lambda_(1)lambda_(2))),lambda=(lambda_(1)lambda_(2))/(lambda_(1)+lambda_(2))`