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180 mL of a hydrocarbon diffuse through ...

180 mL of a hydrocarbon diffuse through a porous membrane in 15 minutes, while 120 mL of `SO_2` under identical conditions diffuse in 20 minutes. What is the molecular mass of the hydrocarbon ?

A

8

B

16

C

24

D

32

Text Solution

Verified by Experts

The correct Answer is:
2
`(r_(1))/(r_(2))=sqrt((M_(SO_(2)))/(M_("hydrocarbon")))(180//15)/(120//20)=sqrt((64)/(M))`
`2=sqrt((64)/(M))=M=16`
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