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At STP, a container has 1 mole of He, 2 ...

At STP, a container has 1 mole of He, 2 mole Ne, 3 mole `O_(2)` and 4 mole `N_(2)`. Without changing total pressure if 2 mole of `O_(2)` is removed . The partial pressure of `O_(2)` will be decreased by :

A

`26%`

B

`40%`

C

`58.33%`

D

`66.66%`

Text Solution

Verified by Experts

The correct Answer is:
3
`P_(O_(2))=(3)/(10)xxP_(T)`
After removing 2 mole of `O_(2)`
`P'_(O_(2))=(1)/(8)xxP_(1)`
Decrease in partial pressure of `O_(2)=((3P_(T))/(10)-(P_(T))/(8))/((3P_(T))/(10))xx100=58.33%`
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