The compressibility factor for nitrogen at 330 K and 800 atm is 1.90 and at 570 K and 200 atm is 1.10. A certain mass of `N_(2)` occupies a volume of 1 `dm^(3)` at 330 K and 800 atm. Calculate volume occupied by same quantity of `N_(2)` gas at 570 K and 200 atm :

Options

A. `1L`
B. `2 L`
C. `3L`
D. `4L`

Answer

4

Explanation

`Z=(PV)/(nRT),1.90=(1xx800)/(nxxRxx330)`
`n=(1xx800)/(1.90xxRxx330)`
`z=1.10=(Vxx200)/(nxxRxx570)`
`1.10=(Vxx200xx1.90xxRxx330)/(800xxRxx570)`
`V=4L`