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At 273 K temperature and 9 atm pressure,...

At 273 K temperature and 9 atm pressure, the compressibility for a gas is 0.9. The volulme of 1 milli-mole of gas at this temperature and pressure is :

A

2.24 litre

B

`0.020 mL`

C

`2.24mL`

D

`22.4mL`

Text Solution

Verified by Experts

The correct Answer is:
3
`Z=(PV)/(nRT)=(V)/(n)=(0.9xx0.082xx273)/(9)=2.24` litre`//`mol
`:. " "` Volume of 1 mili`-` mole of gas `=2.24 mL`
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