Which oxide of carbon is obtained when `K_(4)[Fe(CN)_(6)]` is warmed with concentrated sulphuric acid ?

Options

A. CO
B. `CO_2`
C. `C_3O_2`
D. Both CO and `CO_2`

Explanation

To determine which oxide of carbon is obtained when \( K_4[Fe(CN)_6] \) is warmed with concentrated sulfuric acid, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are potassium ferrocyanide, \( K_4[Fe(CN)_6] \), and concentrated sulfuric acid, \( H_2SO_4 \).

### Step 2: Write the Reaction
When potassium ferrocyanide is treated with concentrated sulfuric acid, it undergoes a decomposition reaction. The general reaction can be represented as:

\[ K_4[Fe(CN)_6] + 6 H_2SO_4 \rightarrow K_2SO_4 + FeSO_4 + (NH_4)_2SO_4 + CO \]

### Step 3: Identify the Products
From the reaction, the products formed include:
- Potassium sulfate (\( K_2SO_4 \))
- Iron(II) sulfate (\( FeSO_4 \))
- Ammonium sulfate (\( (NH_4)_2SO_4 \))
- Carbon monoxide (\( CO \))

### Step 4: Determine the Carbon Oxide
Among the products, the oxide of carbon formed is carbon monoxide (\( CO \)).

### Conclusion
Thus, the oxide of carbon obtained when \( K_4[Fe(CN)_6] \) is warmed with concentrated sulfuric acid is **carbon monoxide (CO)**.

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