What happens when one mole of per oxodisulphuric acid reacts with excess of water (complete hydrolysis ) ?

Explanation

To solve the problem of what happens when one mole of peroxodisulfuric acid reacts with excess water (complete hydrolysis), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Formula of Peroxodisulfuric Acid**:
- The chemical formula for peroxodisulfuric acid is \( \text{H}_2\text{S}_2\text{O}_8 \).

2. **Understand the Reaction with Water**:
- When peroxodisulfuric acid reacts with water, it undergoes hydrolysis. Since we are considering excess water, we will look at the complete hydrolysis of the acid.

3. **Write the Hydrolysis Reaction**:
- The complete hydrolysis of one mole of peroxodisulfuric acid can be represented as:
\[ \text{H}_2\text{S}_2\text{O}_8 + \text{H}_2\text{O} \rightarrow \text{H}_2\text{SO}_4 + \text{H}_2\text{SO}_5 \]
- Here, \( \text{H}_2\text{SO}_4 \) is sulfuric acid and \( \text{H}_2\text{SO}_5 \) is peroxomonosulfuric acid.

4. **Identify the Products**:
- The products formed from the complete hydrolysis of one mole of peroxodisulfuric acid are:
- Sulfuric acid (\( \text{H}_2\text{SO}_4 \))
- Peroxomonosulfuric acid (\( \text{H}_2\text{SO}_5 \))

5. **Conclusion**:
- Therefore, when one mole of peroxodisulfuric acid reacts with excess water, the products are sulfuric acid and peroxomonosulfuric acid.

### Final Answer:
When one mole of peroxodisulfuric acid reacts with excess water, it produces sulfuric acid (\( \text{H}_2\text{SO}_4 \)) and peroxomonosulfuric acid (\( \text{H}_2\text{SO}_5 \)).

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