`SbF_(5)` reacts with `XeF_(4)` to form an adduct. The shapes of cation and anion in the adduct are respectively `:`

Options

A. square planar, trigonal bipyramidal
B. T-shaped, octahedral
C. Square pyramidal, octahedral
D. Square planar, octahedral

Answer

To solve the problem of determining the shapes of the cation and anion formed when \( \text{SbF}_5 \) reacts with \( \text{XeF}_4 \), we can follow these steps:

### Step 1: Identify the Reaction
The reaction between \( \text{SbF}_5 \) and \( \text{XeF}_4 \) leads to the formation of an adduct. The products of this reaction are \( \text{XeF}_3^+ \) (cation) and \( \text{SbF}_6^- \) (anion).

### Step 2: Determine the Hybridization of the Cation \( \text{XeF}_3^+ \)
To find the hybridization of \( \text{XeF}_3^+ \), we can use the formula:
\[ \text{Hybridization} = \frac{1}{2} \left( \text{Valence Electrons of Central Atom} + \text{Number of Surrounding Atoms} + \text{Charge} \right) \]
For \( \text{XeF}_3^+ \):
- Valence electrons of xenon (Xe) = 8
- Number of surrounding fluorine atoms = 3
- Charge on cation = +1

Calculating:
\[ \text{Hybridization} = \frac{1}{2} \left( 8 + 3 - 1 \right) = \frac{1}{2} \times 10 = 5 \quad (\text{which corresponds to } sp^3d) \]

### Step 3: Determine the Shape of the Cation
With \( sp^3d \) hybridization, the shape of \( \text{XeF}_3^+ \) is T-shaped due to the presence of two lone pairs on the xenon atom.

### Step 4: Determine the Hybridization of the Anion \( \text{SbF}_6^- \)
For \( \text{SbF}_6^- \):
- Valence electrons of antimony (Sb) = 5
- Number of surrounding fluorine atoms = 6
- Charge on anion = -1

Calculating:
\[ \text{Hybridization} = \frac{1}{2} \left( 5 + 6 + 1 \right) = \frac{1}{2} \times 12 = 6 \quad (\text{which corresponds to } sp^3d^2) \]

### Step 5: Determine the Shape of the Anion
With \( sp^3d^2 \) hybridization, the shape of \( \text{SbF}_6^- \) is octahedral.

### Final Answer
Thus, the shapes of the cation and anion in the adduct formed from the reaction of \( \text{SbF}_5 \) and \( \text{XeF}_4 \) are:
- Cation: T-shaped
- Anion: Octahedral