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Incorrect order about bond angle is :...

Incorrect order about bond angle is `:`

A

`H_(2)O gt H_(2)S gt H_(2)Se gt H_(2)Te`

B

`C_(2)H_(2) gt C_(2)H_(4) gt CH_(4) gt NH_(3)`

C

`SF_(6) lt NH_(3) lt H_(2)O lt OF_(2)`

D

`ClO_(2) gt H_(2)O gt H_(2)S gt SF_(6)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the incorrect order of bond angles, we will analyze the provided sets of bond angles step by step. ### Step 1: Analyze the first set of bond angles The first set is: \[ \text{H}_2\text{O} > \text{H}_2\text{S} > \text{H}_2\text{Se} > \text{H}_2\text{Te} \] - **Explanation**: In group 16, as we move down from oxygen to tellurium, the electronegativity decreases. This leads to a decrease in the bond angle due to less repulsion between bond pairs. Therefore, the order is correct. ### Step 2: Analyze the second set of bond angles The second set is: \[ \text{C}_2\text{H}_2 > \text{C}_2\text{H}_6 > \text{CH}_4 > \text{NH}_3 \] - **Explanation**: - \(\text{C}_2\text{H}_2\) (acetylene) has a bond angle of 180° (linear). - \(\text{C}_2\text{H}_6\) (ethane) has bond angles of approximately 109.5° (tetrahedral). - \(\text{CH}_4\) (methane) also has bond angles of 109.5°. - \(\text{NH}_3\) (ammonia) has a bond angle of approximately 107° due to lone pair-bond pair repulsion. Thus, the order is correct. ### Step 3: Analyze the third set of bond angles The third set is: \[ \text{SF}_6 > \text{NH}_3 > \text{H}_2\text{O} > \text{OF}_2 \] - **Explanation**: - \(\text{SF}_6\) has bond angles of 90° (octahedral). - \(\text{NH}_3\) has a bond angle of approximately 107°. - \(\text{H}_2\text{O}\) has a bond angle of approximately 104.5°. - \(\text{OF}_2\) has a bond angle less than that of \(\text{H}_2\text{O}\) due to the higher electronegativity of fluorine, which pulls the bond pairs closer to it, leading to a smaller angle. Therefore, this order is incorrect because \(\text{H}_2\text{O}\) should have a larger angle than \(\text{OF}_2\). ### Step 4: Analyze the fourth set of bond angles The fourth set is: \[ \text{ClO}_2 > \text{H}_2\text{O} > \text{H}_2\text{S} > \text{SF}_6 \] - **Explanation**: - \(\text{ClO}_2\) has a bond angle of approximately 118°. - \(\text{H}_2\text{O}\) has a bond angle of approximately 104.5°. - \(\text{H}_2\text{S}\) has a bond angle of approximately 92°. - \(\text{SF}_6\) has bond angles of 90°. This order is correct. ### Conclusion The incorrect order about bond angles is: \[ \text{SF}_6 > \text{NH}_3 > \text{H}_2\text{O} > \text{OF}_2 \]

To solve the question regarding the incorrect order of bond angles, we will analyze the provided sets of bond angles step by step. ### Step 1: Analyze the first set of bond angles The first set is: \[ \text{H}_2\text{O} > \text{H}_2\text{S} > \text{H}_2\text{Se} > \text{H}_2\text{Te} \] - **Explanation**: In group 16, as we move down from oxygen to tellurium, the electronegativity decreases. This leads to a decrease in the bond angle due to less repulsion between bond pairs. Therefore, the order is correct. ...
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