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The correct order of stability to form i...

The correct order of stability to form ionic compounds among `Si^(4+),Al^(3+),Mg^(2+),` and `Na^(+)` is `:`

A

Si4+>Al3+>Mg2+>Na+

B

Al3+>Si4+>Mg2+>Na+

C

Na+>Si4+>Mg2+>Al3+

D

Na+>Mg2+>Al3+>Si4+

Text Solution

Verified by Experts

The correct Answer is:
3
`r=0.529(n^(2))/(Z)A,`
`r_(4)-r_(2)=0.529((16)/(2)-(9)/(2))A=1.851xx10^(-10)m`
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