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Fifth group elements form hydrides to ty...

Fifth group elements form hydrides to type `AH_(3)`. The hydrides have a lone pair of electrons. The hydries are reducing in nature and the reducing power is related to the stability of A-H bonds. The hydrides are covalent and low boiling. Their boiling points depends on their ability to from hydrogen bond and their molecular size which decide the intermolcular forces in the hydrides .
Reducing power of V-group hydrides are in order :

A

`NH_(3) gt PH_(3) gt AsH_(3) gt SbH_(3) gt BiH_(3)`

B

`BiH_(3) gt SbH_(3) gt AsH_(3) gt PH_(3) gt NH_(3)`

C

`PH_(3) gt NH_(3) gt AsH_(3) gt SbH_(3) gt BiH_(3)`

D

`BiH_(3) gt SbH_(3) gt AsH_(3) gt NH_(3) gt PH_(3)`

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To determine the reducing power of the fifth group hydrides (Group 15 elements) of the type \( AH_3 \), we can analyze the properties of these hydrides and how they change down the group. Let's break down the solution step by step. ### Step 1: Identify the Group 15 Hydrides The Group 15 elements that form hydrides include: - Nitrogen (N) → Ammonia (\( NH_3 \)) - Phosphorus (P) → Phosphine (\( PH_3 \)) - Arsenic (As) → Arsenic Hydride (\( AsH_3 \)) - Antimony (Sb) → Antimony Hydride (\( SbH_3 \)) - Bismuth (Bi) → Bismuth Hydride (\( BiH_3 \)) ### Step 2: Understand the Reducing Power The reducing power of these hydrides is related to their ability to donate electrons (or liberate hydrogen). The stability of the \( A-H \) bond plays a crucial role in determining how easily the hydride can release hydrogen. ### Step 3: Analyze the Stability of the \( A-H \) Bonds As we move down the group from nitrogen to bismuth: - The size of the central atom increases. - The bond strength of \( A-H \) bonds decreases due to the larger atomic size and the corresponding increase in bond length. ### Step 4: Relate Stability to Reducing Power - As the thermal stability of the hydrides decreases (weaker \( A-H \) bonds), the tendency of the hydrides to liberate hydrogen increases. - Therefore, the reducing power increases down the group. ### Step 5: Order of Reducing Power Based on the above analysis, the order of reducing power of the Group 15 hydrides is: - \( NH_3 \) (least reducing power, most stable) - \( PH_3 \) - \( AsH_3 \) - \( SbH_3 \) - \( BiH_3 \) (most reducing power, least stable) Thus, the reducing power of the fifth group hydrides in order is: \[ BiH_3 > SbH_3 > AsH_3 > PH_3 > NH_3 \] ### Final Answer The reducing power of the fifth group hydrides is in the order: \[ BiH_3 > SbH_3 > AsH_3 > PH_3 > NH_3 \] ---

To determine the reducing power of the fifth group hydrides (Group 15 elements) of the type \( AH_3 \), we can analyze the properties of these hydrides and how they change down the group. Let's break down the solution step by step. ### Step 1: Identify the Group 15 Hydrides The Group 15 elements that form hydrides include: - Nitrogen (N) → Ammonia (\( NH_3 \)) - Phosphorus (P) → Phosphine (\( PH_3 \)) - Arsenic (As) → Arsenic Hydride (\( AsH_3 \)) - Antimony (Sb) → Antimony Hydride (\( SbH_3 \)) ...
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Fifth group elements form hydrides to type AH_(3) . The hydrides have a lone pair of electrons. The hydries are reducing in nature and the reducing power is related to the stability of A-H bonds. The hydrides are covalent and low boiling. Their boiling points depends on their ability to from hydrogen bond and their molecular size which decide the intermolcular forces in the hydrides . The H-M-H bond angle of V group hydrides decrease from 107^(circ) to 90^(circ) for NH_(3) to SbH_(3) , this is due to:

Fifth group elements form hydrides to type AH_(3) . The hydrides have a lone pair of electrons. The hydries are reducing in nature and the reducing power is related to the stability of A-H bonds. The hydrides are covalent and low boiling. Their boiling points depends on their ability to from hydrogen bond and their molecular size which decide the intermolcular forces in the hydrides . The boiling points of the hydrides of V-group elements are in the order :

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