A metal X on heating in nitrogen gas gives `Y,Y` on treatment with `H_(2)O` gives a colourless gas which when passed through chloroplatinic acid produces yellow precipitate `'Y'` is `:`

Options

A. `Mg(NO_(3))_(2)`
B. `Mg_(3)N_(2)`
C. `NH_(3)`
D. `MgO`

Explanation

To solve the question step by step, we will analyze the information given and deduce the correct answer.

### Step 1: Identify the metal X
The problem states that a metal X reacts with nitrogen gas. A common metal that reacts with nitrogen to form a nitride is magnesium (Mg).

**Hint:** Think about metals that can form nitrides when heated in nitrogen.

### Step 2: Write the reaction of metal X with nitrogen
When magnesium (Mg) is heated in nitrogen (N₂), it forms magnesium nitride (Mg₃N₂). The balanced equation for this reaction is:
\[ 3Mg + N_2 \rightarrow Mg_3N_2 \]

**Hint:** Remember to balance the chemical equation.

### Step 3: Reaction of Y with water
Next, we need to treat the product Y (which is magnesium nitride, Mg₃N₂) with water (H₂O). The reaction produces magnesium hydroxide (Mg(OH)₂) and ammonia (NH₃):
\[ Mg_3N_2 + 6H_2O \rightarrow 3Mg(OH)_2 + 2NH_3 \]

**Hint:** Consider the products formed when metal nitrides react with water.

### Step 4: Identify the colorless gas
In this reaction, ammonia (NH₃) is the colorless gas produced when magnesium nitride reacts with water.

**Hint:** Think about the properties of the products formed in the reaction.

### Step 5: Reaction of the colorless gas with chloroplatinic acid
When ammonia (NH₃) is passed through chloroplatinic acid (H₂PtCl₆), it forms ammonium chloroplatinate, which is a yellow precipitate:
\[ NH_3 + H_2PtCl_6 \rightarrow (NH_4)_2PtCl_6 \]
This precipitate is yellow in color.

**Hint:** Consider the reactions that produce colored precipitates.

### Conclusion
From the analysis, we can conclude that the yellow precipitate Y is ammonium chloroplatinate, which is formed from ammonia reacting with chloroplatinic acid. Therefore, the answer to the question is:

**Y is ammonium chloroplatinate (NH₄)₂PtCl₆.**

### Final Answer
Y is ammonium chloroplatinate (NH₄)₂PtCl₆.

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