`Ph-underset(Me)underset(|)overset(OH)overset(|)(C)-underset(I)underset(|)overset(Me)overset(|)(C)-Phunderset(Delta)overset(AgNO_(3))rarr?` Major product is

Options

A. `Ph-underset(CH_(3))underset(|)overset(OH)overset(|)(C)-underset(Ph)underset(|)overset(NO_(3))overset(|)(C)-Me`
B. `Ph-underset(Ph)underset(|)overset(Me)overset(|)(C)-underset(O)underset(||)(C)-Me`
C. `Ph-underset(O)underset(||)(C)-underset(Ph)underset(|)overset(Me)overset(|)(C)-Me`
D. None of these

Explanation

To solve the problem, we need to analyze the reaction of the given compound with AgNO3 and determine the major product formed. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the Starting Compound
The starting compound is given as:
- **Ph** (Phenyl group)
- **C** (Carbon)
- **Me** (Methyl group)
- **I** (Iodine)
- **C** (Another Carbon)
- **Ph** (Another Phenyl group)

This can be represented as:
\[ \text{Ph}-\text{C}(\text{OH})(\text{Me})-\text{C}(\text{I})(\text{Ph}) \]

### Step 2: Understand the Role of AgNO3
AgNO3 acts as a reagent that provides Ag+ ions. These ions coordinate with the iodine atom (I) in the compound, making it a better leaving group. This is crucial for the next step in the reaction.

### Step 3: Mechanism of the Reaction
1. The Ag+ ion coordinates with the iodine atom, enhancing its ability to leave.
2. The lone pair on the hydroxyl oxygen (OH) can then facilitate the migration of the phenyl group (Ph) from the carbon adjacent to the hydroxyl group.
3. As the phenyl group migrates, the iodine leaves, resulting in the formation of a carbocation intermediate.

### Step 4: Formation of the Product
- The migration of the phenyl group leads to the formation of a double bond (C=O) with the carbon that was originally bonded to the hydroxyl group.
- The final product will have a carbonyl group (C=O) and will also include the remaining groups after the reaction.

Thus, the major product formed is:
\[ \text{Ph}-\text{C}(\text{Me})-\text{C}=\text{O} \]

### Step 5: Identify Byproducts
The byproduct of the reaction is AgI, which is formed when the iodine leaves.

### Final Product
The major product of the reaction is:
\[ \text{Ph}-\text{C}(\text{Me})-\text{C}=\text{O} + \text{AgI} \]

### Conclusion
The major product of the reaction of the given compound with AgNO3 under heating conditions is:
\[ \text{Ph}-\text{C}(\text{Me})-\text{C}=\text{O} \]