Identity Z in the sequence of reactions
`CH_(3)CH_(2)CH = CH_(2) overset(HBr//H_(2)O_(2))to Y overset(C_(2)H_(5)Ona)to Z `

Options

A. `CH_(3)-(CH_(2))_(3)-O-CH_(2)CH_(3)`
B. `(CH_(3))_(2)CH_(2)-O-CH_(2)CH_(3)`
C. `CH_(3)(CH_(2))_(4)-O-CH_(3)`
D. `CH_(3)CH_(2)-CH(CH_(3))-O-CH_(2)OH_(3)`

Answer

1

Explanation

`CH_(3)CO_(2)CH=CH_(2)underset(H_(2)O_(2))overset(HBr)rarrCH_(3)CH_(2)underset(underset(H)(|))(C)H-overset(overset(Br)(|))(C)H_(2)overset(C_(2)H_(6)Na)rarr CH_(3)-(CH_(2))_(3)-OCH_(2)CH_(3)`
HBr in presence of peroxide gives anti Markovnikoff addition product.
`1^(@)` alkyl halide on reaction with `C_(2)H_(5)ONa` give `S_(N)2` reaction.
`CH_(3)CH_(2)CH=CH_(2)underset(H_(2)O_(2))overset(HBr)rarrCH_(3)CH_(2)underset(underset(H)|)(C)H-overset(overset(Br)(|))(C)H_(2)overset(C_(2)H_(5)ONa)rarrCH_(3)-(CH_(2))_(3)-OCH_(2)CH_(3)`