Addition of sodium to bromobenzene in dry ether will produce `:`

Options

A. Biphenyl
B. Benzene
C. Cyclohexane
D. No reaction

Explanation

To solve the question regarding the addition of sodium to bromobenzene in dry ether, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are bromobenzene (C6H5Br) and sodium (Na).

2. **Understand the Reaction Type**: This reaction is an example of the Fittig reaction, which involves the coupling of aryl halides in the presence of sodium and a dry ether solvent.

3. **Write the Reaction**: The reaction can be represented as:
\[ 2 \text{C}_6\text{H}_5\text{Br} + 2 \text{Na} \xrightarrow{\text{dry ether}} \text{C}_6\text{H}_5\text{C}_6\text{H}_5 + 2 \text{NaBr} \]
Here, two molecules of bromobenzene react with sodium to form biphenyl (C12H10) and sodium bromide (NaBr).

4. **Formation of Biphenyl**: In the presence of dry ether, sodium donates electrons to the bromobenzene, leading to the formation of a radical intermediate. This intermediate then couples with another bromobenzene molecule to form biphenyl.

5. **Final Products**: The final products of the reaction are biphenyl (C12H10) and sodium bromide (NaBr).

### Conclusion:
The addition of sodium to bromobenzene in dry ether will produce **biphenyl**.

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