Acetylene react with alkaline `KMnO_(4)` to give

Options

A. Actaldehyde
B. Oxalic acid
C. Acetic acid
D. Glycol

Explanation

To solve the question of what product is formed when acetylene reacts with alkaline KMnO4, we can follow these steps:

### Step 1: Identify the Reactants
- The reactant is acetylene, which has the molecular formula C2H2. It contains a carbon-carbon triple bond (C≡C).

### Step 2: Understand the Reaction Conditions
- The reaction takes place in the presence of cold, dilute alkaline KMnO4. This reagent is known for its oxidizing properties, particularly for oxidizing alkynes.

### Step 3: Reaction Mechanism
- When acetylene (C2H2) reacts with alkaline KMnO4, it undergoes oxidation. The triple bond in acetylene is converted to a double bond, and then further oxidation occurs.

### Step 4: Formation of Intermediate Product
- The first step of oxidation leads to the formation of an intermediate product, which is ethane-1,2-diol (also known as glycol). The reaction can be represented as:
\[ C_2H_2 + [O] \rightarrow C_2H_4(OH)_2 \]
where [O] represents the oxygen supplied by KMnO4.

### Step 5: Further Oxidation
- The ethane-1,2-diol can undergo further oxidation in the presence of KMnO4. This leads to the cleavage of the carbon-carbon bond and the formation of carboxylic acids.
- The final product of this oxidation is oxalic acid (C2H2O4), which can be represented as:
\[ C_2H_4(OH)_2 + [O] \rightarrow C_2O_4H_2 \]

### Step 6: Conclusion
- Therefore, the product formed when acetylene reacts with alkaline KMnO4 is oxalic acid (ethane-1,2-dioic acid).

### Final Answer
The product of the reaction between acetylene and alkaline KMnO4 is **oxalic acid**.

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