When `HCl` gas is passed through propene in the presence of benzoyl peroxide, it gives `:`

Options

A. `2-` chloropropane
B. Allyl chloride
C. No reaction
D. `n-` propyl chloride

Explanation

To solve the question of what product is formed when HCl gas is passed through propene in the presence of benzoyl peroxide, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are propene (C3H6) and hydrogen chloride (HCl). The presence of benzoyl peroxide is also noted, which is a radical initiator.

2. **Understand the Reaction Mechanism**: When HCl reacts with alkenes, the addition of HCl typically follows Markovnikov's rule. However, in the presence of benzoyl peroxide, the reaction can lead to anti-Markovnikov addition due to the formation of free radicals. However, in this specific case, the reaction with HCl does not follow the radical pathway.

3. **Apply Markovnikov's Rule**: According to Markovnikov's rule, the hydrogen atom (H+) from HCl will attach to the carbon atom of the double bond that has more hydrogen atoms, while the chlorine atom (Cl-) will attach to the carbon atom with fewer hydrogen atoms.

- Propene has the structure:
\[ CH_3-CH=CH_2 \]
- The carbon atoms involved in the double bond are:
- Carbon 1 (CH2) has 2 hydrogen atoms.
- Carbon 2 (CH) has 1 hydrogen atom.

4. **Determine the Product**: Based on Markovnikov's rule:
- H+ will attach to Carbon 1 (CH2), and Cl- will attach to Carbon 2 (CH).
- This results in the formation of 2-chloropropane:
\[ CH_3-CHCl-CH_3 \]

5. **Final Product**: The final product of the reaction when HCl is passed through propene in the presence of benzoyl peroxide is 2-chloropropane.

### Conclusion:
The product formed is **2-chloropropane**.

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