`C_(6)H_(5)Cl+CH_(3)Cloverset(Na//"dry ether")rarrC_(6)H_(5)CH_(3)+2NaCl`
This reaction is an example of `:`

Options

A. Wurz reaction
B. Fittig reaction
C. Wurtz-Fitting reaction
D. Frankland reaction

Explanation

To solve the question regarding the reaction of C₆H₅Cl with CH₃Cl in the presence of sodium in dry ether, we can analyze the reaction step by step.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in the given reaction are C₆H₅Cl (chlorobenzene) and CH₃Cl (methyl chloride).

2. **Understand the Role of Sodium (Na)**:
Sodium acts as a reducing agent in this reaction. In the presence of dry ether, sodium can donate electrons to the halides, leading to the formation of radicals.

3. **Formation of Radicals**:
- The sodium reacts with C₆H₅Cl to form a phenyl radical (C₆H₅•) and sodium chloride (NaCl).
- Similarly, sodium reacts with CH₃Cl to form a methyl radical (CH₃•) and sodium chloride (NaCl).

4. **Radical Coupling**:
The phenyl radical (C₆H₅•) and the methyl radical (CH₃•) can then couple together to form the product C₆H₅CH₃ (toluene).

5. **Overall Reaction**:
The overall reaction can be summarized as:
\[ C₆H₅Cl + CH₃Cl \xrightarrow{Na/\text{dry ether}} C₆H₅CH₃ + 2NaCl \]

6. **Identify the Type of Reaction**:
This reaction is an example of a Wurtz-Fittig reaction, which involves the coupling of aryl and alkyl halides in the presence of sodium.

### Conclusion:
The reaction is an example of a **Wurtz-Fittig reaction**.

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