Product
Main product in above reaction is `:`

Answer

1

Explanation

`{:(,2A_(B),hArr,2A_(3),+,3A_(2),+,A_(4)),(t=0,2,,0,,0,,0),(t=t_(aq),2-2alpha,,2alpha,,3alpha,,alpha):}`
`n_(r)=2+4alpha`
given mole fraction of `A_(2)` is `=0.36`.
`0.36=(3alpha)/(2+4alpha)`
`alpha=0.46`
Mole fraction of `A_(B)=(2-2alpha)/(2+4alpha)=(2-2xx0.46)/(2+4xx0.46)=0.28`