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The uncertainties in position and the ve...

The uncertainties in position and the velocity of a particle are `10^(10)` m and 10×`10^(−24).sec^(−1)` respectively. The mass of the particle in kg is

A

h/4π×`10^(−13)` ​

B

h×4×`10^33`

C

`h/ (4π)`×`10 ^(−13)`

D

None

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The correct Answer is:
To find the mass of the particle using the uncertainty principle, we can follow these steps: ### Step 1: Understand the Uncertainty Principle The uncertainty principle states that the product of the uncertainties in position (Δx) and momentum (Δp) is greater than or equal to a constant, which is given by: \[ \Delta x \cdot \Delta p \geq \frac{h}{4\pi} \] where \( h \) is Planck's constant. ### Step 2: Relate Momentum to Mass and Velocity Momentum (p) is defined as the product of mass (m) and velocity (v): \[ p = m \cdot v \] Thus, the uncertainty in momentum (Δp) can be expressed as: \[ \Delta p = m \cdot \Delta v \] ### Step 3: Substitute into the Uncertainty Principle Substituting Δp into the uncertainty principle gives us: \[ \Delta x \cdot m \cdot \Delta v \geq \frac{h}{4\pi} \] ### Step 4: Rearrange to Solve for Mass Rearranging the equation to solve for mass (m) yields: \[ m \geq \frac{h}{4\pi \cdot \Delta x \cdot \Delta v} \] ### Step 5: Substitute the Given Values We are given: - \( \Delta x = 10^{10} \, \text{m} \) - \( \Delta v = 10 \times 10^{-24} \, \text{s}^{-1} \) Now, we can substitute these values into the equation. First, we need to calculate \( \Delta x \cdot \Delta v \): \[ \Delta x \cdot \Delta v = 10^{10} \cdot (10 \times 10^{-24}) = 10^{10} \cdot 10^{-23} = 10^{-13} \] ### Step 6: Use the Value of Planck's Constant Planck's constant \( h \) is approximately \( 6.626 \times 10^{-34} \, \text{Js} \). Now substituting this into our equation: \[ m \geq \frac{6.626 \times 10^{-34}}{4\pi \cdot 10^{-13}} \] ### Step 7: Calculate the Mass Calculating the denominator: \[ 4\pi \approx 12.566 \] Thus, \[ m \geq \frac{6.626 \times 10^{-34}}{12.566 \times 10^{-13}} \approx \frac{6.626}{12.566} \times 10^{-34 + 13} \approx 0.528 \times 10^{-21} \, \text{kg} \] ### Final Result The mass of the particle is approximately: \[ m \approx 0.528 \times 10^{-21} \, \text{kg} \]

To find the mass of the particle using the uncertainty principle, we can follow these steps: ### Step 1: Understand the Uncertainty Principle The uncertainty principle states that the product of the uncertainties in position (Δx) and momentum (Δp) is greater than or equal to a constant, which is given by: \[ \Delta x \cdot \Delta p \geq \frac{h}{4\pi} \] ...
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In a certain experiments to measure the ratio of charge to mass of elementry particles, a surprising result was obtained in which two particle, a surprising result was obtained in which two particles moved in such a way that the distance between them always remained constant. It was also noticed that this two-particle system was isolated from all other particles and no force was acting on this system except the force between these two mases. After careful observation followed bu intensive calculation, it was deduced that velocity of these two particles was always opposite in direction and magnitude of velocity was 10^(3) ms^(-1) and 2 xx 10^(3) ms^(-1) for first and second particle, respectively, and mass of these particles were 2 xx 10^(-30) kg and 10^(-30)kg , respectively. Distance between them were 12Å(1Å = 10^(- 10)m). Acceleration of the first particle was

In a certain experiments to measure the ratio of charge to mass of elementry particles, a surprising result was obtained in which two particle, a surprising result was obtained in which two particles moved in such a way that the distance between them always remained constant. It was also noticed that this two-particle system was isolated from all other particles and no force was acting on this system except the force between these two mases. After careful observation followed bu intensive calculation, it was deduced that velocity of these two particles was always opposite in direction and magnitude of velocity was 10^(3) ms^(-1) and 2 xx 10^(3) ms^(-1) for first and second particle, respectively, and mass of these particles were 2 xx 10^(-30) kg and 10^(-30)kg , respectively. Distance between them were 12Å(1Å = 10^(- 10)m). Acceleration of the second particle was

RESONANCE ENGLISH-ALKYL HALIDE, ALCOHOL, PHENOL, ETHER-ORGANIC CHEMISTRY(Alkyl Halide, Alcohol,Phenol,Ether)
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