Home
Class 12
CHEMISTRY
Density of a 2.05 M solution of acetic a...

Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is:

A

`3.28` mol `kg^(-1)`

B

`2.28` mol `kg^(-1)~

C

`0.44` mol `kg^(-1)`

D

`1.14` mol `kg^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Molality, `m=(M)/(1000d-MM_(2))xx1000`
where `M=` molarity, `d=` density, `M_(2)=` molecular mass
`m=(2.05)/(1000xx1.02-2.05xx60)=2.28 "mol" kg^(-1)`
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    RESONANCE ENGLISH|Exercise EXERCISE-3(PART-3)|30 Videos

  • SOLUTIONS

    RESONANCE ENGLISH|Exercise Advabced Level Problems (PART-1)|71 Videos

  • SOLUTIONS

    RESONANCE ENGLISH|Exercise EXERCISE-3(PART-1)|14 Videos

  • SOLUTION AND COLLIGATIVE PROPERTIES

    RESONANCE ENGLISH|Exercise PHYSICAL CHEMITRY (SOLUTION & COLLIGATIVE PROPERTIES)|52 Videos

  • STEREOISOMERISM

    RESONANCE ENGLISH|Exercise EXERCISE (PART III : PRACTICE TEST-2 (IIT-JEE (ADVANCED PATTERN))|23 Videos

Similar Questions

Explore conceptually related problems

The density of a 1M solution of acetic acid in water is 2g/mL. The molality of the solution is

The density of 0.06 M solution of Kl in water is 1.006 g mL^(-1) . Determine the molality of this solution (K = 39, I = 127 "amu")

3.0 molal NaOH solution has a density of 1.110 g//mL . The molarity of the solution is:

The freezing point of 0.20 M solution of week acid HA is 272.5 K . The molality of the solution is 0.263 "mol" kg^(-1) . Find the pH of the solution on adding 0.25 M sodium acetate solution. K_(f) of water = 1.86 K m^(-1)

The density of 2M solution of NaCl is 1.25 g mL^(-1) . The molality of the solution is

The density of 3M solution of NaCl is 1.25 g mL^(-1) . The molality of the solution is

The density of 1 M solution of NaCl is 1.0585 g mL^(-1) . The molality of the solution is

The density of 3 M solution of NaCl is 1.25 "g mL"^(-1) . The molality of the solution is :

The depression of freezing point of a solution of acetic acid in benzene is – 0.2°C. If the molality of acetic acid is 0.1 m, then find the ratio of the normal mass to the abnormal mass. (Assume Kf of acetic acid = 4.0°C m-1)

The density of 3 molal solution of NaOH is 1.110g mL^(-1) . Calculate the molarity of the solution.