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On mixing, heptane and octane form an id...

On mixing, heptane and octane form an ideal solution. At `373K` the vapour pressure of the two liquid components (heptane and octane) are `105 kPa` and `45 kPa` respectively. Vapour pressure of the solution obtained by mixing `25.0` of heptane and `35g` of octane will be (molar mass of heptane `= 100 g mol^(-1)` and of octane `= 114 g mol^(-1))`:-

A

`72.0 kPa`

B

36.1kPA`

C

`96.2kPa`

D

`144.5kPa`

Text Solution

Verified by Experts

The correct Answer is:
A
`P_(T)=X_("Heptane")P^_("Heptane")^(@)+X_("Octane")P_("Octane")^(@)`
`=(0.25)/(0.557)xx105+(0.307)/(0.557)xx45`
`47.127+24.80=71.92=72 kPa`
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