Home
Class 12
CHEMISTRY
K(f) for water is 1.86 K kg mol^(-1). If...

`K_(f)` for water is `1.86 K kg mol^(-1)`. If your automobile radiator holds `1.0 kg` of water, how many grams of ethylene glycol `(C_(2)H_(6)O_(2))` must you add to get the freezing point of the solution lowered to `-2.8^(@)C` ?

A

`72g`

B

`93g`

C

`39g`

D

`27g`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaT_(f)=ixxK_(f)xxm`
2.8=1xx1.86xx(x)/(62xx1)`
`x=(2.8xx62)/(1.86)=93gm`
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    RESONANCE ENGLISH|Exercise EXERCISE-3(PART-3)|30 Videos

  • SOLUTIONS

    RESONANCE ENGLISH|Exercise Advabced Level Problems (PART-1)|71 Videos

  • SOLUTIONS

    RESONANCE ENGLISH|Exercise EXERCISE-3(PART-1)|14 Videos

  • SOLUTION AND COLLIGATIVE PROPERTIES

    RESONANCE ENGLISH|Exercise PHYSICAL CHEMITRY (SOLUTION & COLLIGATIVE PROPERTIES)|52 Videos

  • STEREOISOMERISM

    RESONANCE ENGLISH|Exercise EXERCISE (PART III : PRACTICE TEST-2 (IIT-JEE (ADVANCED PATTERN))|23 Videos

Similar Questions

Explore conceptually related problems

45 g of ethylene glycol (C_(2) H_(6)O_(2)) is mixed with 600 g of water. The freezing point of the solution is (K_(f) for water is 1.86 K kg mol^(-1) )

The freezing point of 0.05 m solution of glucose in water is (K1 = 1.86°C m^(-1) )

45 g of ethylene glycol C_(2)H_(6)O_(2) is mixed with 600 g of water. Calculate (a) the freezing point depression and (b) the freezing point of solution. Given K_(f)=1.86 K kg mol^(-1) .

0.1 mole of sugar is dissolved in 250 g of water. The freezing point of the solution is [K_(f) "for" H_(2)O = 1.86^(@)C "molal"^(-1)]

If 0.1 m aqueous solution of calcium phosphate is 80% dissociated then the freezing point of the solution will be (K_f of water = 1.86K kg mol^(-1))

45 g of ethylene glycol C_(2)H_(4)O_(2) is mixed with 600 g of water. Calculate (a) the freezing point depression and (b) the freezing point of solution. Given K_(f)=1.86 K kg mol^(-1) .

A 0.1 molal aqueous solution of a weak acid is 30% ionized. If K_(f) for water is 1.86^(@)C//m , the freezing point of the solution will be.

In a 2.0 molal aqueus solution of a weak acid HX the degree of disssociation is 0.25. The freezing point of the solution will be nearest to: ( K_(f)=1.86 K kg "mol"^(-1) )

The molal freezing point constant of water is 1.86 K m^(-1) . If 342 g of cane sugar (C_(12)H_(22)O_(11)) is dissolved in 1000 g of water, the solution will freeze at

How many grams of methyl alcohol should be added to 10 litre tank of water to prevent its freezing at 268K ? (K_(f) for water is 1.86 K kg mol^(-1))