The osmotic pressure of a solution containing 0.5 mol of solute per litre at 323 K is

Answer

`2.69` atm

Explanation

`HAhArrH^(+)+A^(-)`
[H^(+)]=Calpha=10^(-2)~
`therefore alpha=(10^(-2))/(0.1)=10^(-1)=0.1`
`therefore` Total particles in solution `=[1+a=1+0.1=1.1`
Then `p=C.S.T(1+alpha)`
`=0.1xx0.0821xx298xx1.1`
`=2.69` atm