An aqueous solution of glucose boils at `100.03^(@)C`.The molal elevation constant for water is `0.5 kmol^(-1)kg`. The number of molecules of glucose in the solution containing `100g` of water is

Answer

`X_(A)=((sqrt(P_(A)^(0)P_(B)^(0))-P_(B)^(0)))/((P_(A)^(0)-P_(B)^(0))),P=sqrt(P_(A)^(0)P_(B)^(0))`

Explanation

`P_("benzenen")^(@)=X_(A)PA^(@)+(1-X_(A))P_(B)^(@)`
`(1)/(P_(T))=(Y_(A))/(P_(B)^(0))+((1-Y_(A)))/(P_(B)^(0))`
calculate `(X_(A)-Y_(A)) &` maximise it
`X_(A)=(sqrt(P_(A)^(0)P_(B)^(0))-P_(B)^(0))/((P_(A)^(0)-P_(B)^(0)))`
& `P_(T)=sqrt(P_(A)^(0)P_(B)^(0))`
`X_(A)=((sqrt(P_(A)^(0)P_(B)^(0))-P_(B)^(0)))/((P_(A)^(0)-P_(B)^(0))),P=sqrt(P_(A)^(0)P_(B)^(0))`