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Select in incorrect match...

Select in incorrect match

A

`Hg,Cu,Pbimplies` Self reduction

B

`Mn_(3)O_(4),B_(2)O_(3)implies` Reduction by aluminium

C

`Zr, Ti,Niimplies` Vapour phase refining

D

Molten `MgCl_(2)+CaCl_(2)+NaCl implies` Hoop's process (electrolysis)

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The correct Answer is:
To solve the question of selecting the incorrect match, we will analyze each option provided in the question step by step. ### Step 1: Analyze the first part - Self-reduction of metals 1. **Identify the metals mentioned**: Hg (mercury), Cu (copper), and Pb (lead). 2. **Check self-reduction reactions**: - For **Hg**: The reaction is \(2 \text{HgO} + \text{HgS} \rightarrow 3 \text{Hg} + \text{SO}_2\). This indicates that mercury undergoes self-reduction. - For **Cu**: The reaction is \(2 \text{Cu}_2\text{O} + \text{Cu}_2\text{S} \rightarrow 6 \text{Cu} + \text{SO}_2\). This indicates that copper undergoes self-reduction. - For **Pb**: The reaction is \(2 \text{PbO} + \text{PbS} \rightarrow 3 \text{Pb} + \text{SO}_2\). This indicates that lead undergoes self-reduction. **Conclusion**: Hg, Cu, and Pb all undergo self-reduction correctly. ### Step 2: Analyze the second part - Reduction by aluminum 1. **Identify the compounds**: Mn3O4 and B2O3. 2. **Check reduction reactions**: - For **Mn3O4**: The reaction is \(3 \text{Mn}_3\text{O}_4 + 8 \text{Al} \rightarrow 9 \text{Mn} + 4 \text{Al}_2\text{O}_3\). This indicates that manganese oxide undergoes reduction by aluminum. - For **B2O3**: The reaction is \(2 \text{B}_2\text{O}_3 + 6 \text{Al} \rightarrow 4 \text{B} + 3 \text{Al}_2\text{O}_3\). This indicates that boron oxide also undergoes reduction by aluminum. **Conclusion**: Both Mn3O4 and B2O3 undergo reduction by aluminum correctly. ### Step 3: Analyze the third part - Vapor phase refining 1. **Identify the methods**: Van Arkel method, Mohr process, and Hooke's process. 2. **Check the applications**: - **Van Arkel method**: Used for refining titanium and zirconium. - **Mohr process**: Used for refining nickel. - **Hooke's process**: This is used for electrolytic refining of aluminum, which typically involves molten fluorides, not chlorides. **Conclusion**: The statement regarding Hooke's process is incorrect because it mentions molten MgCl2, CaCl2, and NaCl, which are not used in the Hooke's process. ### Final Answer The incorrect match is the statement regarding the use of molten MgCl2, CaCl2, and NaCl in the Hooke's process. Therefore, the answer is: **Option 4 is the incorrect match.** ---

To solve the question of selecting the incorrect match, we will analyze each option provided in the question step by step. ### Step 1: Analyze the first part - Self-reduction of metals 1. **Identify the metals mentioned**: Hg (mercury), Cu (copper), and Pb (lead). 2. **Check self-reduction reactions**: - For **Hg**: The reaction is \(2 \text{HgO} + \text{HgS} \rightarrow 3 \text{Hg} + \text{SO}_2\). This indicates that mercury undergoes self-reduction. - For **Cu**: The reaction is \(2 \text{Cu}_2\text{O} + \text{Cu}_2\text{S} \rightarrow 6 \text{Cu} + \text{SO}_2\). This indicates that copper undergoes self-reduction. - For **Pb**: The reaction is \(2 \text{PbO} + \text{PbS} \rightarrow 3 \text{Pb} + \text{SO}_2\). This indicates that lead undergoes self-reduction. ...
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