The area of cross section of the two arms of a hydraulic press are `1cm^(2)` and `10cm^(2)` respectively . A force of `5N` is applied on the water in the thinner arm. What force should be applied on the water in the thicker arm so that the water may remain in equilibrium?
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Explanation

In equilibrium, the pressures at the two surfaces should be equal as they lie in the same horizontal level. If the atmospheric pressure is `P` and a force `F` is applied to maintain the equilibrium, the pressures are
`P_(0) + (50N)/(10cm^(2))` and `P_(0) + (F)/(1 cm^(2))` respectively.
This given `F = 5 N`.