An open rectangular tank 1.5 m wide 2m deep ad 2 m long is half filled with water. It is accelerated horizontally at `3.27m//s^(2)` in the direction of its length determine the depth of water at each end of tank.

Explanation

`tan theta = (a)/(g) = (1)/(3)`
Depth at corner `'A'`
`= 1 - 1.5 tantheta`
`= 0.5 m`
Depth at corner `'B'`
`= 1 + 1.5 tan theta = 1.5 m`