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A soild ball of density half that of wat...

A soild ball of density half that of water falls freely under gravity from a height of 19.6 m and then enters water. Upto what depth will the ball go. How much time will it take to come again to the water surface? Neglect air resistandce and viscosity effects in water. (Take `g=9.8 m//S^(2))`.

Text Solution

Verified by Experts

The correct Answer is:
`19.6 m, 4 sec`
In water `a = g uarr`

So, by symmetry in air and water in acceleration distance travelled travelled `= 19.6 m`.
`t = 2sqrt(2h//g) = 2sqrt(2 xx 19.6//9.8) = 4` sec.
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