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In a hydraulic lift, used at a service s...

In a hydraulic lift, used at a service station the radius of the large and small piston are in the ratio of `20 : 1`. What weight placed on the small piston will be sufficient of lift a car of mass 1200 Kg ?

A

`3.75` kg

B

`37.5` kg

C

`7.5` kg

D

`75` kg

Text Solution

Verified by Experts

The correct Answer is:
A

`(m_(1)g)/(A_(1)) = (m_(2)g)/(A_(2))`
Solving. `m_(2) = 3.75 kg`.
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