Home
Class 11
PHYSICS
There is a circular tube in a vertical p...

There is a circular tube in a vertical plane. Two liquids which do not mix and of densities `d_(1)` and `d_(2)` are filled in the tube. Each liquid subtends `90^(@)` angle at centre. Radius joining their interface makes an angle `alpha` with vertical . rartio `d_(1)//d_(2)` is

A

`(1 + sin alpha)/(1 - sin alpha)`

B

`(1 + cos alpha)/(1 - cos alpha)`

C

`(1 + tan alpha)/(1 - tan alpha)`

D

`(1 + sin alpha)/(1 - cos alpha)`

Text Solution

Verified by Experts

The correct Answer is:
C

`Rsinalpha d_(2) + Rcosalpha d_(2) + R(1 - cosalpha)d_(1)`
`= R(1 - sinalpha )d_(1)`
`(sinalpha + cosalpha) d_(2) = d_(1)(cosalpha - sinalpha)`
`rArr (d_(1))/(d_(2)) = (1 + tanalpha)/(1 - tanalpha)`
Promotional Banner

Topper's Solved these Questions

  • FLUID MECHANICS

    RESONANCE ENGLISH|Exercise Advanced Level Problems|8 Videos

  • FLUID MECHANICS

    RESONANCE ENGLISH|Exercise Exercise- 3 PART - I|17 Videos

  • ELECTROSTATICS

    RESONANCE ENGLISH|Exercise Exercise|52 Videos

  • FULL TEST 1

    RESONANCE ENGLISH|Exercise Exercise|30 Videos

Similar Questions

Explore conceptually related problems

There is a circular tube in a vertical plane. Two liquids which do not mix and of densities d_1 and d_2 are filled in the tube. Each liquid subtends 90^@ angle at centre. Radius joining their interface make an angle alpha with vertical. Ratio (d_1)/(d_2) is :

If equal masses of two liquids of densities d_(1) and d_(2) are mixed together, the density of the mixture is

A thin uniform circular tube is kept in a vertical plane. Equal volume of two immiscible liquids whose densites are rho_(1) and rho_(2) fill half of the tube as shown. In equilibrium the radius passing through the interface makes an angle of 30^(@) with vertical. The ratio of densities (rho_(1)//rho_(2)) is equal to

A uniform long tube is bent into a circle of radius R and it lies in vertical plane. Two liquids of same volume but densities rho " and " delta fill half the tube. The angle theta is

A small uniform tube is bent into a circle of radius r whose plane is vertical. Equal volumes of two fluids whose densities are rho and sigma(rhogtsigma) fill half the circle. Find the angle that the radius passing through the interface makes with the vertical.

A circular tube of uniform cross section is filled with two liquids densities rho_(1) and rho_(2) such that half of each liquid occupies a quarter to volume of the tube. If the line joining the free surfaces of the liquid makes an angle theta with horizontal find the value of theta.

Two non - viscous, incompressible and immiscible liquids of densities (rho) and (1.5 rho) are poured into the two limbs of a circular tube of radius ( R) and small cross section kept fixed in a vertical plane as shown in fig. Each liquid occupies one fourth the cirumference of the tube. Find the angle (theta) that the radius to the interface makes with the verticles in equilibrium position.

An object weights m_(1) in a liquid of density d_(1) and that in liquid of density d_(2) is m_(2) . The density of the object is

A tube in vertical plane is shown in figure. It is filled with a liquid of density rho and its end B is closed. Then the force exerted by the fluid on the tube at end B will be: [Assume the radius of the tube to be negligible in comparison to l]

Two discs have same mass and thickness. Their materials are of densities d_(1) and d_(2) . The ratio of their moments of inertia about an axis passing through the centre and perpendicular to the plane is