A rod of length `l` and total charge `'q'` which is uniformly distributed is rotating with angular velocity `omega` about an axis passing through the centre of rod and perpendicular to rod. Find the magnitude of magnetic dipole moment (in Amp. `m^(2)`) of rod. If `q=4C, omega=3rad//s` and `l=2m`

Explanation

To find the magnetic dipole moment \( m \) of a uniformly charged rotating rod, we can follow these steps:

### Step 1: Define the charge distribution
Given a rod of length \( l \) and total charge \( q \) uniformly distributed, we can express the charge per unit length as:
\[ \lambda = \frac{q}{l} \]
where \( \lambda \) is the linear charge density.
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