A block of mass 1 kg is given horizontal velocity `v_(0)=10sqrt(3)(m)/(s)` from origin along x-axis on rough horizontal surface where coefficient of friction `mu=mu_(0)(1+(x)/(10))` where `mu_(0)=1`. It is found that maximum power loss due to friction is `100K` in S.I units what is value of K?

Answer

2

Explanation

`V-(dv)/(dx)=-mu_(0)g(1+X/10)`
`impliesV=sqrt(300-20x-x^(2))`
`=(1+x/10)mg sqrt(300-20x-x^(2))`
`P_(max)=200`