A Connot engine having an efficiency of `(1)/(10)` as heat engine, is usee as a refrigerator. If the wrok done on the system is 10j .the amount of energy absorbed from the reseroir at lower temperature is

Options

A. `99J`
B. `90J`
C. `1J`
D. `100J`

Answer

B

Explanation

For carnot engine using as refrigerator.
`W=Q_(2)((T_(1))/(T_(2))-1)`
It is given `ea=1/10implieseta=1(T_(2))/(T_(1))`
`implies(T_(2))/(T_(1))=9/10`
So` Q_(2)=90J` (as `W=10J`)