A block of mass `m_(1)` lies on the top of fixed wedge as shown in fig. and another block of mass `m_(2)` lies on top of wedge which is free to move as shown in fig. At time t=0 both the blocks are released from rest from a vertical height h above the respective horizontal surface on which the wedge is placed as shown. There is no friction between block and wedge in both the figures. Let `T_(1)` and `T_(2)` be the time taken by the blocks respectively to just reach the horizontal surface. then

Options

A. `T_(1)gtT_(2)`
B. `T_(1)ltT_(2)`
C. Magnitude of normal reaction on block of mass `m_(2)` is equal to that on the block of mass `m_(1)`
D. After falling through same height (less than `h`) from top of wedge, the speed of block of mass `m_(2)` is less than that of block of mass `m_(1)`

Answer

A

Explanation

We draw axes of each along the incline and normal to incline. The component of acceleration for each block are as shown where is acceleration of wedge is figure 2.
It is obvious that vertical component of acceleration is larger for block in figure 2.
`:.T_(1)gtT_(2)`