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The point P(1,1) is transiated parallel ...

The point `P(1,1)` is transiated parallel to `2x=y`in the first quadrant through a unith distance. The coordinates of the point in new position are

A

`(1+-2/(sqrt(5)),1+-1/(sqrt(5)))`

B

`(1+-1/(sqrt(5)),1+-2/(sqrt(5)))`

C

`(1/(sqrt(5)),2/(sqrt(5)))`

D

`(2/(sqrt(5)),1/(sqrt(5)))`

Text Solution

Verified by Experts

The correct Answer is:
B
New position of `P` is `(1+-costheta, 1+-sintheta)` where `tantheta=2`
`thetaepsilon(0,pi)`
Hence the points are `(1+-1/(sqrt(5)),1+-2/(sqrt(5)))`
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